document.write( "Question 920069: Solve 3x - 4 ≤ 2 or 2x + 11 ≥ -1. \n" ); document.write( "
Algebra.Com's Answer #569278 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
\"3x-4%3C=2\" or \"2x%2B11%3E=-1\" \r
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\n" ); document.write( "\n" ); document.write( "\"3x-4%2B4%3C=2%2B4\" or \"2x%2B11%3E=-1-11\" \r
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\n" ); document.write( "\n" ); document.write( "\"3x%3C=6\" or \"2x%3E=-12\" \r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=3\" or \"x%3E=-6\" \r
\n" ); document.write( "\n" ); document.write( "and since every real number satisfies either one or the other, the solution is all real nembers
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