document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935870>Question 935870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what should be subtracted from 2x+3y+7 to get the sum of the terms 3x-2y+3 and 2x+2y-3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569218 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> subtracted from 2x+3y+7 to get the sum of the terms 3x-2y+3 and 2x+2y-3\r<BR>\n" );
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document.write( "subtracted from 2x+3y+7 to get\r<BR>\n" );
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document.write( " the sum of the terms 3x-2y+3 and 2x+2y-3<BR>\n" );
document.write( "=5x<BR>\n" );
document.write( "Let A be subtracted\r<BR>\n" );
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document.write( "2x+3y+7 - A =5x\r<BR>\n" );
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document.write( "A= 2x+3y+7 -5x\r<BR>\n" );
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document.write( "A= -3x+3y+7\r<BR>\n" );
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