document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935867>Question 935867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first and the last term of an arithmetic progression are 9 and 93.If the sum of the arithmetic progression is 663,find the number of terms. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569209 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
document.write( "\n" );
document.write( "Sn = n/2 (a+l)\r<BR>\n" );
document.write( "\n" );
document.write( "a= first term<BR>\n" );
document.write( "l = last term<BR>\n" );
document.write( "663=n/2(9+93)\r<BR>\n" );
document.write( "\n" );
document.write( "663*2 = n(102)\r<BR>\n" );
document.write( "\n" );
document.write( "663*2/102= n\r<BR>\n" );
document.write( "\n" );
document.write( "=13\r<BR>\n" );
document.write( "\n" );
document.write( "Number of terms = 13 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );