document.write( "Question 935779: How do I prove that the angle bisector of the vertex angle of an isosceles triangle is an altitude? \n" ); document.write( "
Algebra.Com's Answer #569198 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The angle bisector (ray OB) divides the vertex angle AOC into two congruent angles (angle AOB and angle COB). \n" ); document.write( "It also divides the triangle into two triangles (triangle AOB and triangle COB). \n" ); document.write( "You can prove that those two triangles are congruent. \n" ); document.write( "They have one pair of congruent angles (angle AOB and angle COB). \n" ); document.write( "Those angles are flanked by pairs of congruent sides, \n" ); document.write( "because side OA is congruent with side OC (by definition of isosceles triangle), \n" ); document.write( "and side OB is congruent with itself. \n" ); document.write( "So, by SAS congruency, triangle AOB and triangle COB are congruent. \n" ); document.write( "Then, by CPCTC (Congruent Parts of Congruent Triangles are Congruent), \n" ); document.write( "angle ABO and angle CBO are congruent, \n" ); document.write( "but since points A, B, and C are colinear, \n" ); document.write( "angles ABO and CBO being congruent means they are right angles. \n" ); document.write( " \n" ); document.write( "Segment BO is the altitude of triangle ACO, \n" ); document.write( "because it is perpendicular to base AC, \n" ); document.write( "and goes from a point on line AC to vertex O. \n" ); document.write( " |