document.write( "Question 935849: solve for n:
\n" ); document.write( "[(3)]^{(81)^n}=[(81)]^{(3)^n}
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Algebra.Com's Answer #569194 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"highlight%283%5E%2881%5En%29=81%5E%283%5En%29%29\" ...........\"81=9%2A9=3%5E2%2A3%5E2=3%5E4\" substitute it\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%283%5E%28%283%5E4%29%5En%29=%283%5E4%29%5E%283%5En%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%283%5E%283%5E%284n%29%29=3%5E%284%2A3%5En%29%29\" ....same base, then same exponents\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%283%5E%284n%29=4%283%29%5En%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%283%5E%284n%29%2F3%5En=4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%283%5E%284n-n%29=4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%283%5E%283n%29=4%29\" ....use log base \"10\" to solve for \"n\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28log%283%5E%283n%29%29=log%284%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28%283n%29log%283%29=log%282%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%283n=2log%282%29%2Flog%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28blue%28n+=+%282log%282%29%29%2F%283log%283%29%29%29%29\"...exact solution\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28green%28n=0.42062%29%29\" ...approximate solution\r
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\n" ); document.write( "\n" ); document.write( "check this solution:\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%283%5E%2881%5E%280.42062%29%29=+81%5E%283%5E%280.42062%29%29%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"highlight%281070.37=1070.36%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"highlight%281070=1070%29+\"\r
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