document.write( "Question 79285: Please help!!!!!!\r
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document.write( "1) (3x+14)^2+25=0\r
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document.write( "2) 25x^2=13\r
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document.write( "3) 2(x-5)^2=3\r
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document.write( "4) x^2+4x+4=7\r
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document.write( "Thanks!!!!!! \n" );
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Algebra.Com's Answer #56915 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Please help!!!!!! \n" ); document.write( "1) (3x+14)^2+25=0 \n" ); document.write( "FYI: a^2+b^2=(a+bi)(a-bi) \n" ); document.write( "Your Problem: \n" ); document.write( "[3x+14+5i][3x+14-5i] \n" ); document.write( "x=(1/3)(-145-5i) or x=(1/3)(-14+5i) \n" ); document.write( "========================== \n" ); document.write( "2) 25x^2=13 \n" ); document.write( "x^2=13/25 \n" ); document.write( "x=(sqrt13)/5 or x=-(sqrt13)/5 \n" ); document.write( "============================ \n" ); document.write( "3) 2(x-5)^2=3 \n" ); document.write( "(x-5)^2=3/2 \n" ); document.write( "(x-5)=sqrt(3/2) or x-5=-(sqrt(3/2)) \n" ); document.write( "x=5+(sqrt6)/6 or x=5-[(sqrt6)/6] \n" ); document.write( "============================= \n" ); document.write( "4) x^2+4x+4=7 \n" ); document.write( "(x+2)^2=7 \n" ); document.write( "(x+2)=sqrt7 or (x+2)=-sqrt7 \n" ); document.write( "x=-2+sqrt7 or x=-2-sqrt7 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |