document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935770>Question 935770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the second term A.P is 1 and the fifth term is -11 find the sum of its first 10 term. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569121 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the second term A.P is 1 and the fifth term is -11 find the sum of its first 10 term.<BR>\n" );
document.write( "solution<BR>\n" );
document.write( "a+d=1<BR>\n" );
document.write( "a+4d=-11   by subtraction <BR>\n" );
document.write( "-3d=12<BR>\n" );
document.write( "d=-4   a-4=1 than a=5<BR>\n" );
document.write( "AP will be as   5,1,-3.....<BR>\n" );
document.write( "sum of 10 terms = n[2a+(n-1)d]/2<BR>\n" );
document.write( "=10[10+9x(-4)]/2<BR>\n" );
document.write( "=10[10-36]/2= 5x(-26)= -130\r<BR>\n" );
document.write( "\n" );
document.write( "answer -130<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );