document.write( "Question 935773: the ratio of the volumes of two similar rectangular prisms is 125:64. What is the ratio of their base areas? \n" ); document.write( "
Algebra.Com's Answer #569119 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the formula for the volume of a rectangular prism is area of the base * the height.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the base is equal to length * width.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for the volume of a rectangular prism becomes length * width * height.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the ratio of the volume of a three sided figure is the ratio of their corresponding sides cubed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so if the ratio of their volumes is 125/64, then the ratio of their corresponding sides id 5/4 because 5^3 = 125 and 4^3 = 64.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the base area is equal to length * widfth, then the ratio of the areas becomes 5^2 / 4^2 which is equal to 25/16.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the ratio of the base area becomes 25/16.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to confirm, use an example:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "original prism has dimensions as shown below: \n" ); document.write( "length = 20 \n" ); document.write( "width = 40 \n" ); document.write( "height = 60 \n" ); document.write( "volume = 20 * 40 * 60 = 48000 \n" ); document.write( "base area = 20 * 40 = 800\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "prims that has sides in a ratio of 5/4 to original prism is shown below: \n" ); document.write( "length = 20 * 5/4 = 25 \n" ); document.write( "width = 40 * 5/4 = 50 \n" ); document.write( "height = 60 * 5/4 = 75 \n" ); document.write( "volume = 25 * 50 * 75 = 93750 \n" ); document.write( "base area = 25 * 50 = 1250\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ratio of the volumes = 93750 / 48000 = 1.953125 \n" ); document.write( "ratio of the base areas = 1250 / 800 = 1.5625\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "125/64 = 1.953125 \n" ); document.write( "25/16 = 1.5625\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formulas work.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the ratio of the volume is 125/64 \n" ); document.write( "the ratio of the base area is 25/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |