document.write( "Question 935765: Good day! My question goes here, \"How many 5-digit even numbers can be formed out of the digits 2, 4, 5, 8 and 9 without repetition?\" \n" ); document.write( "
Algebra.Com's Answer #569084 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "Consider the 5-digit number as blanks: _ _ _ _ _\r
\n" ); document.write( "\n" ); document.write( "The last digit must be even. Since we have three even numbers (\"2\",\"4\",\"8\"). The last digit can be filled in \"3\" ways. Since repetition is not allowed, we can fill out the rest blanks in ways,\"3\" ways,\"2\" ways, and \"1\" way.\r
\n" ); document.write( "\n" ); document.write( "\"1%2A+2+%2A+3%2A+4+%2A3+=+72\" ways ; so, \"72\" 5-digit even numbers can be formed
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