document.write( "Question 935751: Worker A finishes the job in 10 hrs; Worker B finishes it in 12 hrs, and worker C finishes it jn 15 hrs. After worker A worked alone for 2 hrs, and then B worked alome for 4 hours, how many hours will it take C alone to finish the remaining work?
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Algebra.Com's Answer #569042 by josmiceli(19441)\"\" \"About 
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What fraction of the job did A finish in \"+2+\" hrs?
\n" ); document.write( "A's rate is: ( 1 job ) / ( 10 hrs )
\n" ); document.write( "\"+%28+1%2F10+%29%2A2+=+1%2F5+\"
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\n" ); document.write( "That means there is \"+4%2F5+\" of the job left to do
\n" ); document.write( "B's rate is ( 1 job ) / ( 12 hrs )
\n" ); document.write( "B's fraction of the fraction left to do is:
\n" ); document.write( "\"+%28+1%2F12+%29%2A4+=+1%2F3+\"
\n" ); document.write( "\"+%281%2F3%29%2A%284%2F5%29+=+4%2F15+\" is the fraction now done
\n" ); document.write( "That means there is \"+11%2F15+\" of the job left to do
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\n" ); document.write( "C's rate is ( 1 job ) / ( 15 hrs )
\n" ); document.write( "C can do \"+11%2F15+\" of the job in:
\n" ); document.write( "\"+%28+11%2F15%29%2A15+=+11+\" hrs to finish the work\r
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