document.write( "Question 935751: Worker A finishes the job in 10 hrs; Worker B finishes it in 12 hrs, and worker C finishes it jn 15 hrs. After worker A worked alone for 2 hrs, and then B worked alome for 4 hours, how many hours will it take C alone to finish the remaining work?
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Algebra.Com's Answer #569039 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x = amount of time it takes worker C alone to finish the job\r
\n" ); document.write( "\n" ); document.write( "Worker A works at the rate of 1/10 of the job per hour
\n" ); document.write( "Worker B rate is 1/12 of the job per hour
\n" ); document.write( "Worker C rate is 1/15 of the job per hour
\n" ); document.write( "In 2 hours, worker A finishes (1/10)*2=2/10 = 1/5 of the job
\n" ); document.write( "In 4 hours worker B finishes (1/12)*4=1/3 of the job
\n" ); document.write( "Together A and B have finished 1/5 + 1/3=3/15+5/15=8/15 of the job leaving 7/15 yet to be finished
\n" ); document.write( "So our equation to solve is:
\n" ); document.write( "(1/15)*x=7/15
\n" ); document.write( "x=7 hours
\n" ); document.write( "CK
\n" ); document.write( "(1/10)*2+(1/12)*4+(1/15)*7 should equal 1 job
\n" ); document.write( "Hope this helps---ptaylor
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