document.write( "Question 935697: what is the rate of decrease if a number decreases from 2,000 to 1,450 ? \n" ); document.write( "
Algebra.Com's Answer #568995 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your decrease is 2000 - 1450 = 550.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the rate of decrease is equal to 550 / 2000 = .275\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the decrease is then calculated from the rate as .275 * 2000.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the rate is normally described as a function of time, like one year or two years or 10 years or 3 months or 5 days or whatever.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "assuming that the time interval between when the value was 2000 and 1450 was 1 year, then the rate of decrease would be .275 per year.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "if the rate of decrease was constant, then 200 would become 2000 - .275 * 2000 = 1450 after the first year and then become 1450 - .275 * 1450 = 1051.25 after the second year, etc.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );