document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935684>Question 935684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the diagonal of a rectangle has a length 7 feet and the rectangles area is 16 square feet find the number of feet in the rectangles perimeter  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568972 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diagonal of the rectangle is a hypotenuse for each of the two triangles that it forms.  \r<BR>\n" );
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document.write( "x and y, length and \"width\",<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28x%5E2%2By%5E2=7%5E2%2Cxy=16%29 ALIGN=MIDDLE  ALT=\"system%28x%5E2%2By%5E2=7%5E2%2Cxy=16%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=16%2Fx ALIGN=MIDDLE  ALT=\"y=16%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" >, substitute this.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B%2816%2Fx%29%5E2=49 ALIGN=MIDDLE  ALT=\"x%5E2%2B%2816%2Fx%29%5E2=49\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E4%2B16=49x%5E2 ALIGN=MIDDLE  ALT=\"x%5E4%2B16=49x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E4-49x%5E2%2B16=0 ALIGN=MIDDLE  ALT=\"x%5E4-49x%5E2%2B16=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, quadratic form.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=%2849%2Bsqrt%2849%5E2-4%2A16%29%29%2F2 ALIGN=MIDDLE  ALT=\"x%5E2=%2849%2Bsqrt%2849%5E2-4%2A16%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=%2849%2Bsqrt%282337%29%29%2F2 ALIGN=MIDDLE  ALT=\"x%5E2=%2849%2Bsqrt%282337%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "2337=3*779=3*19*41\r<BR>\n" );
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document.write( "Computing into base-ten values,<BR>\n" );
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document.write( "x=0.328736 and y=48.671264<BR>\n" );
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document.write( "Perimeter would be  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%282%280.328736%2B48.671264%29%29 ALIGN=MIDDLE  ALT=\"highlight%282%280.328736%2B48.671264%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and you can choose what accuracy you want, or recalculate x and y to greater accuracy and use that if you want.\r<BR>\n" );
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document.write( "The quadratic form equation found in x would be the same if found in y, so the PLUS_OR_MINUS forms of the general solution method will give separately the x and the y.  Both are found and understood as positive values. </SPAN>\n" );
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