document.write( "Question 935662: Patty and Tom live 345 miles apart. they decide to drive to meet one another. Patty leaves at noon, traveling at an average rate of 45 mi/h, and Tom leaves at 3:00 pm traveling at an average speed of 60 mi/h. At what time will they meet? \n" ); document.write( "
Algebra.Com's Answer #568938 by TimothyLamb(4379)\"\" \"About 
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\n" ); document.write( "s = d/t
\n" ); document.write( "t = d/s
\n" ); document.write( "d = st
\n" ); document.write( "---
\n" ); document.write( "a = distance traveled by patty when tom departs:
\n" ); document.write( "a = 45*3
\n" ); document.write( "a = 135
\n" ); document.write( "---
\n" ); document.write( "b = distance between them when tom departs:
\n" ); document.write( "b = 345 - a
\n" ); document.write( "b = 345 - 135
\n" ); document.write( "b = 210
\n" ); document.write( "---
\n" ); document.write( "speed of patty and tom relative to each other:
\n" ); document.write( "s = 45 + 60
\n" ); document.write( "s = 105
\n" ); document.write( "---
\n" ); document.write( "time after tom departs when they meet:
\n" ); document.write( "t = d/s
\n" ); document.write( "t = 210/105
\n" ); document.write( "t = 2 hours
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "time when they meet:
\n" ); document.write( "3:00 pm + 2 hours = 5:00 pm
\n" ); document.write( "---
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