document.write( "Question 935662: Patty and Tom live 345 miles apart. they decide to drive to meet one another. Patty leaves at noon, traveling at an average rate of 45 mi/h, and Tom leaves at 3:00 pm traveling at an average speed of 60 mi/h. At what time will they meet? \n" ); document.write( "
Algebra.Com's Answer #568935 by josmiceli(19441)\"\" \"About 
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How far does Patty get in the \"+3+\" hours
\n" ); document.write( "before Toby leaves?
\n" ); document.write( "\"+d%5B1%5D+=+45%2A3+\"
\n" ); document.write( "\"+d%5B1%5D+=+135+\" mi
\n" ); document.write( "-------------------
\n" ); document.write( "Start a stopwatch when Toby leaves
\n" ); document.write( "Let \"+t+\" = time in hours on
\n" ); document.write( "stopwatch when they meet
\n" ); document.write( "Let \"+d+\" = distance in miles that
\n" ); document.write( "Toby travels until they meet
\n" ); document.write( "-------------------------
\n" ); document.write( "Patty's equation:
\n" ); document.write( "(1) \"+345+-d+-+135+=+45t+\"
\n" ); document.write( "Toby's equation:
\n" ); document.write( "(2) \"+d+=+60t+\"
\n" ); document.write( "----------------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+345+-+60t+-+135+=+45t+\"
\n" ); document.write( "(1) \"+105t+=+210+\"
\n" ); document.write( "(1) \"+t+=+2+\"
\n" ); document.write( "They will meet 2 hrs after Toby leaves
\n" ); document.write( "3 PM + 2 hrs = 5 PM
\n" ); document.write( "is when they meet
\n" ); document.write( "---------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+60t+\"
\n" ); document.write( "(2) \"+d+=+60%2A2+\"
\n" ); document.write( "(2) \"+d+=+120+\" mi
\n" ); document.write( "and
\n" ); document.write( "(1) \"+345+-d+-+135+=+45t+\"
\n" ); document.write( "(1) \"+345+-120+-+135+=+45%2A2+\"
\n" ); document.write( "(1) \"+90+=+90+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
\n" );