document.write( "Question 933336: The length of a rectangle is 5 more than the width. If the perimeter is 42 ft, what are the dimensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #568927 by Fombitz(32388) $\"\"$ $\"About$

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$\"L=W%2B5\"$
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\n" ); document.write( "For a rectangle,
\n" ); document.write( " $\"P=2%2A%28L%2BW%29\"$
\n" ); document.write( "Substituting from above,
\n" ); document.write( " $\"P=2%2A%28W%2B5%2BW%29=42\"$
\n" ); document.write( " $\"2W%2B5=21\"$
\n" ); document.write( " $\"2W=16\"$
\n" ); document.write( " $\"W=8\"$
\n" ); document.write( "THen,
\n" ); document.write( " $\"L=8%2B5\"$
\n" ); document.write( " $\"L=13\"$
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