document.write( "Question 935602: A train from London to Birmingham takes 2 hours for the journey. If the average speed of the train were decreased by 5 miles per hour, the train would take 12 minutes longer.
\n" ); document.write( "Find the distance from London to Birmingham and the average speed of the train, using simultaneous equations
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Algebra.Com's Answer #568907 by TimothyLamb(4379)\"\" \"About 
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x = distance between the cities (miles)
\n" ); document.write( "y = speed of the train (mph)
\n" ); document.write( "---
\n" ); document.write( "s = d/t
\n" ); document.write( "t = d/s
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\n" ); document.write( "at normal speed:
\n" ); document.write( "y = x/2
\n" ); document.write( "2y = x
\n" ); document.write( "---
\n" ); document.write( "at reduced speed:
\n" ); document.write( "y - 5 = x/(2 + 12/60)
\n" ); document.write( "y - 5 = x/2.2
\n" ); document.write( "2.2y - 2.2*5 = x
\n" ); document.write( "---
\n" ); document.write( "put the system of linear equations into standard form
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\n" ); document.write( "x - 2y = 0
\n" ); document.write( "x - 2.2y = -11
\n" ); document.write( "---
\n" ); document.write( "copy and paste the above standard form linear equations in to this solver:
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\n" ); document.write( "---
\n" ); document.write( "solution:
\n" ); document.write( "x = distance between the cities (miles) = 110
\n" ); document.write( "y = speed of the train (mph) = 55
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