document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935634>Question 935634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A part of $8900 is invested at 6% and the rest at 4%. the annual income from the 4 % exceeds the income from the 6% investment by $74. Find the amount of each investment. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568873 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A part of $8900 is invested at 6% and the rest at 4%. the annual income from the 4 % exceeds the income from the 6% investment by $74. Find the amount of each investment.<BR>\n" );
document.write( "let $x for 6% and $8900-x at 4%<BR>\n" );
document.write( "as per conditions <BR>\n" );
document.write( ".4(8900-x)-.6x=74<BR>\n" );
document.write( "3560.0 -.4x-.6x=74<BR>\n" );
document.write( "3560-1.0x=74<BR>\n" );
document.write( "3560-74=x<BR>\n" );
document.write( "3486=x<BR>\n" );
document.write( "other investment will be 8900-3486= $5414<BR>\n" );
document.write( "answer $5414 at 4% and $$3486 at 6% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );