document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935625>Question 935625</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I know I am suppose to use the method of Ratios but this is so confusing to me please help!\r<BR>\n" );
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document.write( "Many tires come with 13/32 inch of tread on them.<BR>\n" );
document.write( "The first 2/32 inch wears off quickly (say during the<BR>\n" );
document.write( "first 1000 miles). From then on the tire wears uniformly<BR>\n" );
document.write( "and more slowly. A tire is considered “worn<BR>\n" );
document.write( "out” when only 2/32 inch of tread is left.\r<BR>\n" );
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document.write( "a. How many 32nds of an inch of useable tread<BR>\n" );
document.write( "does a tire have after 1000 miles?\r<BR>\n" );
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document.write( "b. A tire has traveled 20,000 miles and has 5/32<BR>\n" );
document.write( "inch of tread remaining. At this rate, how many<BR>\n" );
document.write( "total miles should the tire last before it is considered<BR>\n" );
document.write( "worn out? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568868 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you start at 13/32 of an inch of tread.\r<BR>\n" );
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document.write( "after 1000 miles, you lost 2/32 of an inch of tread, so you have 13/32 - 2/32 = 11/32 of an inch of tread left.\r<BR>\n" );
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document.write( "after 20000 miles, you have 5/32 of an inch of tread left.\r<BR>\n" );
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document.write( "from 1000 miles to 20000 miles, you lost 11/32 - 5/32 = 6/32 of tread after traveling an additional 19000 miles.\r<BR>\n" );
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document.write( "the tire is worn when you get to 2/32 of an inch of tread left.\r<BR>\n" );
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document.write( "from 5/32 to 2/32 is 3/32.\r<BR>\n" );
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document.write( "you wear off another 3/32 of tread between 5/32 of an inch of tread on your tire and 2/32 of an inch of your tire.\r<BR>\n" );
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document.write( "you know that you wore off 6/32 of tread in 19000 miles.\r<BR>\n" );
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document.write( "that's between 1000 miles and 20000 miles that we calculated earlier.\r<BR>\n" );
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document.write( "your ratio will be:\r<BR>\n" );
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document.write( "(6/32) / 19000 = (3/32) / x\r<BR>\n" );
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document.write( "x will represent the additional number of miles you travel before the tire is declared worn out.\r<BR>\n" );
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document.write( "multiply both sides of this equation by x and divide both sides of this equation by (6/32) and you get:\r<BR>\n" );
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document.write( "x = (3/32) * 19000 / (6/32)\r<BR>\n" );
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document.write( "since 19000 / (6/32) is the same as 19000 * (32/6), your equation becomes:\r<BR>\n" );
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document.write( "x = (3/32) * (32/6) * 19000 which becomes:\r<BR>\n" );
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document.write( "x = 3/6 * 19000 which becomes:\r<BR>\n" );
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document.write( "x = 9500 miles.\r<BR>\n" );
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document.write( "your tire will be declared worn out in an additional 9500 miles.\r<BR>\n" );
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document.write( "the total miles the tire will have traveled is 1000 + 19000 + 9500 which is equal to 29500 miles.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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