document.write( "Question 935621: please help me solving it.i tried it again and again but still not getting it. some amount out of $7000 was lent at 6% p.a. and the remaining was lent at 4%p.a.
\n" ); document.write( "if the total simple interest in 5 years was $1600, find the amount lent 6% p.a
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Algebra.Com's Answer #568861 by MathLover1(20850)\"\" \"About 
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Solution;
\n" ); document.write( "suppose $ \"x\" was lent at \"6\"% per annum:
\n" ); document.write( "thus,
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\n" ); document.write( "\"%28x%2A6%2A5%29%2F100+%2B+%28%287000-x%29%2A4%2A5%29%2F100=1600\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%2F10+%2B+%2814000-2x%29%2F10=1600\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%2F10+%2B+%28cross%2814000%297000-cross%282%29x%29%2Fcross%2810%295=1600\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%2F10%2B%287000-x%29%2F5=1600\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%2B%287000-x%292=1600%2A10\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%2B14000-2x=16000\"\r
\n" ); document.write( "\n" ); document.write( "Therefore \r
\n" ); document.write( "\n" ); document.write( "\"x=16000-14000\"\r
\n" ); document.write( "\n" ); document.write( "$ \"x=2000\"
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