document.write( "Question 935579: Sheila needs 30 mL of a 19.2% acid solution for a chemistry experiment. She has a 12% acid solution and an 84% acid solution. How many milliliters of the 12% solution does she need to make the mixture?
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Algebra.Com's Answer #568825 by TimothyLamb(4379)\"\" \"About 
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x = mL of 84% acid solution
\n" ); document.write( "y = mL of 12% acid solution
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\n" ); document.write( "x + y = 30
\n" ); document.write( "0.84x + 0.12y = 0.192*30
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\n" ); document.write( "put the system of linear equations into standard form
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\n" ); document.write( "x + y = 30
\n" ); document.write( "0.84x + 0.12y = 5.76
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\n" ); document.write( "copy and paste the above standard form linear equations in to this solver:
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\n" ); document.write( "answer:
\n" ); document.write( "x = mL of 84% acid solution = 3
\n" ); document.write( "y = mL of 12% acid solution = 27
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