document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935497>Question 935497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2)PQR is a straight line PQ=4PR P(-4,-1) Q(6,11) find the co-ordinate of R? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568748 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568748\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PQR is a straight line PQ=4PR P(-4,-1) Q(6,11) find the co-ordinate of R<BR>\n" );
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document.write( "length of PQ = sqrt[(11--1)^2+(6--4)^2] = sqrt[144+100) <BR>\n" );
document.write( "= sqrt(244) = 2sqrt(61)<BR>\n" );
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document.write( "PR = (1/4)PQ = (1/2)sqrt(61)<BR>\n" );
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document.write( "Comment: since PQ is larger than PR, R must be between P and Q<BR>\n" );
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document.write( "Ratio of PQ to PR = 2sqrt(61)/(1/2)sqrt(61) = 4:1<BR>\n" );
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document.write( "So R is 1/4 of the way from P to Q<BR>\n" );
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document.write( "Let the coordinates of R be (x,y)<BR>\n" );
document.write( "x = (1/4)(6--4) = (1/4)(10) = 2.5<BR>\n" );
document.write( "y = (1/4)(11--1) = (1/4)(12) = 3<BR>\n" );
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document.write( "Ans:: R = (2.5,3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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