document.write( "Question 935501: Suppose you double the radius of a right cylinder. Explain why the surface area is not doubled using the proper formula. \n" ); document.write( "
Algebra.Com's Answer #568724 by Theo(13342)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "the formula for surface area of a right cylinder is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sa1 = 2*pi*r*h + 2*pi*r^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "double the surface area and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sa2 = 2*(2*pi*r*h + 2*pi*r^2) which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sa2 = 4*pi*r*h + 4*pi*r^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "double the radius of the original formula and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sa3 = 2*pi*(2*r)*h + 2*pi*(2*r)^2 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sa3 = 2*pi*2*r*h + 2*pi*2^2*r^2 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sa3 = 4*pi*r*h + 2*pi*4*r^2 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sa3 = 4*pi*r*h + 8*pi*r^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the surface area is doubled when you double the radius, then sa2 would be equal to sa3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it is not.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sa2 = 4*pi*r*h + 4*pi*r^2 \n" ); document.write( "sa3 = 4*pi*r*h + 8*pi*r^2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |