document.write( "Question 935490: A number consists of two digits such that the digit in ten's place is less by 2 than the digit in the units place. Three times the number added to 6/7 times the number obtained by reserving the digits equals 108. the sum of the digits in the number is: \n" ); document.write( "
Algebra.Com's Answer #568715 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let the tens digit = \n" ); document.write( "Let the units digit = \n" ); document.write( "The value of the number is: \n" ); document.write( " \n" ); document.write( "------------------------- \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "------------------------------------------ \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and, by substitution: \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and, since \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "------------- \n" ); document.write( "The number is \n" ); document.write( "The sum of the digits is \n" ); document.write( "------------------------------ \n" ); document.write( "check answer: \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK \n" ); document.write( " |