document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935463>Question 935463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The annual precipitation for one city is normally distributed with a mean of 72 inches and a standard deviation of 3.5 inches. Fill in the blanks.\r<BR>\n" );
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document.write( "In 99.7% of the years, the precipitation in this city is between __________ and __________ inches.\r<BR>\n" );
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document.write( "Apply the 68-95-99.7 rule to this questions.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568702 by </B><A HREF=/tutors/aboutme.mpl?userid=TimothyLamb><B>TimothyLamb(4379)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TimothyLamb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TimothyLamb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the 68-95-99.7 rule:<BR>\n" );
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document.write( "in a normal distribution, 68.27% of the values lie within one standard deviation of the mean, 95.45% of the values lie within two standard deviations of the mean, and 99.73% of the values lie within three standard deviations of the mean.<BR>\n" );
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document.write( "3 sigma:<BR>\n" );
document.write( "72-3.5*3 = 61.5<BR>\n" );
document.write( "72+3.5*3 = 82.5<BR>\n" );
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document.write( "answer:<BR>\n" );
document.write( "In 99.7% of the years, the precipitation in this city is between 61.5 and 82.5 inches.<BR>\n" );
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