document.write( "Question 935388: In a 200 mile bike ride, Duva realized that if she could average 1 mile per hour faster than she did on her last 200 mile bike ride, she would finish 1 hour sooner. How long did she spend on her last 200 mile ride?\r
\n" ); document.write( "\n" ); document.write( "*Write the answer in minutes, and round to the nearest 10 minutes*
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Algebra.Com's Answer #568613 by josgarithmetic(39620)\"\" \"About 
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r, speed of the last bike ride;
\n" ); document.write( "d, each distance of bike rides;
\n" ); document.write( "t, time of the last bike ride;
\n" ); document.write( "k, time difference, also given equal to rate difference;
\n" ); document.write( "d=200;
\n" ); document.write( "k=1.\r
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\n" ); document.write( "\n" ); document.write( "______________________rate____________time___________distance
\n" ); document.write( "LAST__________________r_______________t_______________d
\n" ); document.write( "THIS__________________r+k_____________t-k_____________d\r
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\n" ); document.write( "\n" ); document.write( "The unknown variables are r and t.
\n" ); document.write( "The system equations are \"system%28rt=d%2C%28r%2Bk%29%28t-k%29=d%29\".
\n" ); document.write( "Work with this system as thoroughly as you can completely in symbols to simplify and
\n" ); document.write( "to solve for r and t. You will obtain a quadratic equation through the process.\r
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\n" ); document.write( "\n" ); document.write( "\"rt%2Bkt-rk-k%5E2=d\"
\n" ); document.write( "\"d%2Bkt-kr-k%5E2=d\"
\n" ); document.write( "\"kt-kr-k%5E2=0\", and already knowing that k=1,
\n" ); document.write( "\"t-r-1=0\"
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\n" ); document.write( "Using other equation, r=d/t.
\n" ); document.write( "Substituting,
\n" ); document.write( "\"t-d%2Ft-1=0\"
\n" ); document.write( "\"t%28t-d%2Ft-1%29=t%2A0\"
\n" ); document.write( "\"t%5E2-d-t=0\"
\n" ); document.write( "\"t%5E2-t-d=0\"
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\n" ); document.write( "\"t=%28-1%2Bsqrt%281%5E2-4%2A1%28-d%29%29%29%2F2\"
\n" ); document.write( "\"highlight_green%28t=%28-1%2Bsqrt%281%2B4d%29%29%2F2%29\", which is in HOURS.\r
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