document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935399>Question 935399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The model distance = 3.30+0.235*(speed) can be used to predict the stopping distance (in feet) for a car traveling at a specific speed (in mph). According to this model, about how much distance will a car going 65 mph need to stop?<BR>\n" );
document.write( "A) 27.0 feet<BR>\n" );
document.write( "B)4.3 feet<BR>\n" );
document.write( "C) 729.0 feet <BR>\n" );
document.write( "D)18.6 feet <BR>\n" );
document.write( "E)345.0 feet  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568612 by </B><A HREF=/tutors/aboutme.mpl?userid=TimothyLamb><B>TimothyLamb(4379)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TimothyLamb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TimothyLamb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = 3.30+0.235*(65)<BR>\n" );
document.write( "d = 18.575<BR>\n" );
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document.write( "answer:<BR>\n" );
document.write( "D)18.6 feet<BR>\n" );
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