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document.write( "Find the coefficient of x^4 in the binomial expansion of (5+2x)^7
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document.write( "(with steps please)
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document.write( "Formula for a specific term in an expansion: (a + b)n = nCr-1(a)n-(r-1)(b)r-1, where r = term number
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document.write( "(5 + 2x)7
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document.write( "Observing the binomial, it’s seen that the x-term, or “b” in the expansion of the binomial needs to be to the 4th power.
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document.write( "Thus, the term that produces
is the term that needs to be determined. Thus, we can say that:
, and that:
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document.write( "4 = r – 1
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document.write( "4 + 1 = r
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document.write( "r, or term number = 5\r
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document.write( "Using the formula for a specific term in an expansion, term 5 or the 5th term can be determined, as follows:
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document.write( " (a + b)n = nCr-1(a)n-(r-1)(b)r-1, where r = term number
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document.write( "(5 + 2x)7 = 7C5-1(5)7-(5-1)(2x)5-1, where r = 5th term
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document.write( "(5 + 2x)7 = 7C4(5)7-4(2x)4
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document.write( "(5 + 2x)7 = 35(5)3(2x)4
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document.write( "(5 + 2x)7 = 4,375(16)x4
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document.write( "(5 + 2x)7 = 70,000x4
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document.write( "Thus, the
term, or 5th term of the binomial expansion:
, is 70,000x4, which means
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document.write( "that the coefficient is
\r
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document.write( "Not to be confused, if the binomial's expressions were rearranged from
to
,
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document.write( "then
or
would be the 4th term.
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document.write( "You can do the check!!
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document.write( "===================
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document.write( "Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
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