document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935326>Question 935326</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you:\r<BR>\n" );
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document.write( "Make a the subject (with steps) of :\r<BR>\n" );
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document.write( "3(a+4)=ac+5f </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568513 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you want to solve for a in terms of the other variables is what i think you mean.<BR>\n" );
document.write( "start with:<BR>\n" );
document.write( "3(a+4) = ac + 5f<BR>\n" );
document.write( "distribute the multiplication to get:<BR>\n" );
document.write( "3a + 12 = ac + 5f<BR>\n" );
document.write( "subtract 12 from both sides of the equation to get:<BR>\n" );
document.write( "3a = ac + 5f - 12<BR>\n" );
document.write( "subtract ac from both sides of the equation to get:<BR>\n" );
document.write( "3a - ac = 5f - 12<BR>\n" );
document.write( "factor out the a to get:<BR>\n" );
document.write( "a * (3 - c) = 5f - 12<BR>\n" );
document.write( "divide both sides of the equation by (3 - c) to get:<BR>\n" );
document.write( "a = (5f - 12) / (3 - x)<BR>\n" );
document.write( "that's your solution.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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