document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79201>Question 79201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> First off, we are asked to find the value of x. Then, we are given a triangle. One angle measures 133 degrees. Another is (x+20)degrees. Another is 2x degrees. How do we solve these types of problems? We have 6 different ones. Thanks.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56851 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56851\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> On problems involving triangles and unknown angles, you can use the well-known fact that the sum of the angles in any plane triangle is always 180 degrees.<BR>\n" );
document.write( "So, set up the equation to add the given angles:<BR>\n" );
document.write( "133 + (x+20) + (2x) = 180 Combine like-terms.<BR>\n" );
document.write( "133 + 3x + 20 = 180 Simplify.<BR>\n" );
document.write( "153 + 3x = 180 Subtract 153 from both sides.<BR>\n" );
document.write( "3x = 27 Finally, divide both sides by 3.<BR>\n" );
document.write( "x = 9 degrees. </SPAN>\n" );
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