document.write( "Question 935308: A 6 Liter solution is 60% HCL acid. How much of this must be taken out and be replaced with water to reduce the solution into 45% HCL acid? \n" ); document.write( "
Algebra.Com's Answer #568483 by TimothyLamb(4379)\"\" \"About 
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x = liters of 60% HCL acid/water = 40% HCL water/acid
\n" ); document.write( "y = liters of 100% water
\n" ); document.write( "z = liters of 45% HCL acid/water = 55% HCL water/acid
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\n" ); document.write( "z = 6
\n" ); document.write( "0.40x + 1.00y = 0.55z
\n" ); document.write( "x + y = z
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\n" ); document.write( "put the system of linear equations into standard form
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\n" ); document.write( "z = 6
\n" ); document.write( "0.40x + 1.00y - 0.55z = 0
\n" ); document.write( "x + y - z = 0
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\n" ); document.write( "x = liters of 60% HCL acid/water = 40% HCL water/acid = 4.5
\n" ); document.write( "y = liters of 100% water = 1.5
\n" ); document.write( "z = liters of 45% HCL acid/water = 55% HCL water/acid = 6
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\n" ); document.write( "answer:
\n" ); document.write( "replace 1.5 liters of 60% HCL acid with pure water
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