document.write( "Question 935308: A 6 Liter solution is 60% HCL acid. How much of this must be taken out and be replaced with water to reduce the solution into 45% HCL acid? \n" ); document.write( "
Algebra.Com's Answer #568482 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
You remove x liters from the solution\r
\n" ); document.write( "\n" ); document.write( "replace it with water\r
\n" ); document.write( "\n" ); document.write( "remaining amount - 6-x of 60%\r
\n" ); document.write( "\n" ); document.write( " percent ---------------- quantity
\n" ); document.write( "water 0.00% ---------------- x liter
\n" ); document.write( "Acid 60.00% ------ 6 - x liter
\n" ); document.write( "Mixture 45.00% ---------------- 6
\n" ); document.write( "Total 6 liter
\n" ); document.write( "0.00% x + 60.00% ( 6 - x ) = 45.00% * 6
\n" ); document.write( "0 x + 60 ( 6 - x ) = 270
\n" ); document.write( "0 x + 360 - 60 x = 270
\n" ); document.write( "0 x - 60 x = 270 -360
\n" ); document.write( "-60 x = -90
\n" ); document.write( "/ -60
\n" ); document.write( " x = 1.5 liter water
\n" ); document.write( " 4.5 liter 60.00% Acid
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );