document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79203>Question 79203</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My son and I can't find the solution to this question. 148 people attend a 5 day camp. The chef needs 9 lbs of food for each child and 12 lbs for each adult.He needs a total of 1410 lbs of food. How many children and how many adults attend camp? We figured that there are 26 adults and 122 children but we can't set it up using two variables. Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56848 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56848\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> always glad to help a parent\r<BR>\n" );
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document.write( "let a=number of adults and c=number of children ... a+c=148 ... a=148-c and (foodwise) 12a+9c=1410\r<BR>\n" );
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document.write( "substituting ... 12*(148-c)+9c=1410 ... 1776-3c=1410 ... c=122 ... and a=26 </SPAN>\n" );
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