document.write( "Question 79180: This is actually two equations using variables using the substitution method.
\n" ); document.write( "I've been stuck on this for a long time.\r
\n" ); document.write( "\n" ); document.write( "x-3y=2
\n" ); document.write( "x+2y=-3\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #56840 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve the system of equations:
\n" ); document.write( "1) \"x-3y+=+2\"
\n" ); document.write( "2) \"x%2B2y+=+-3\"
\n" ); document.write( "Rewrite equation 1) as:
\n" ); document.write( "1) \"x+=+3y%2B2\" and substitute for x in equation 2)
\n" ); document.write( "2a) \"%283y%2B2%29%2B2y+=+-3\" Simplify and solve for y.
\n" ); document.write( "\"5y%2B2+=+-3\" Subtract 2 from both sides.
\n" ); document.write( "\"5y+=+-5\" Divide both sides by 5.
\n" ); document.write( "\"y+=+-1\" Now substitute this for y in equation 1) and solve for x.
\n" ); document.write( "\"x+=+3y%2B2\"
\n" ); document.write( "\"x+=+3%28-1%29%2B2\"
\n" ); document.write( "\"x+=+-1\"
\n" ); document.write( "The solution is: (-1, -1)
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