document.write( "Question 935200: if x plus y = a and xy = b, then the value of 1/x to the power of 3 plus 1/y to the power of 3 is equal to ? \n" ); document.write( "
Algebra.Com's Answer #568380 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The other two tutors above gave INCORRECT answers \r\n" );
document.write( "because they didn't know that you are not supposed \r\n" );
document.write( "to have x's and y's in the final answer, but only \r\n" );
document.write( "a's and b's.\r\n" );
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\n" ); document.write( "if x plus y = a and xy = b, then the value of 1/x to the power of 3 plus 1/y to the power of 3 is equal to ?
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document.write( "\"system%28x%2By=a%2C%0D%0Axy+=+b%29\"\r\n" );
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document.write( "Now we need to find \"x%5E2%2By%5E2\".  We square both side of\r\n" );
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document.write( "\"x%2By=a\"\r\n" );
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document.write( "\"x%5E2%2B2xy%2By%5E2=a%5E2\"\r\n" );
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document.write( "\"x%5E2%2B2b%2By%5E2=a%5E2\"\r\n" );
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document.write( "\"x%5E2%2By%5E2=a%5E2-2b\"\r\n" );
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document.write( "So\r\n" );
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document.write( "answer:\r\n" );
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document.write( "\"a%28a%5E2-3b%29%2Fb%5E3\" \r\n" );
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document.write( "Edwin
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