document.write( "Question 935180: Ahmad travels from his house to his friend's house averaging 60 miles per hour. On the return trip, he averages 50 miles per hour. His total driving time for the round trip is 11 hours. What is the distance, in miles, between Ahmad's house and his friend's house? \n" ); document.write( "

Algebra.Com's Answer #568325 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+d+\"$ = the distance in miles
\n" ); document.write( "between their houses
\n" ); document.write( "Let $\"+t+\"$ = the time in hours for
\n" ); document.write( "Ahmad to go from his house
\n" ); document.write( "to his friend's house
\n" ); document.write( "------------------------------
\n" ); document.write( "Equation for Ahmad's house to friend's house:
\n" ); document.write( "(1) $\"+d+=+60t+\"$
\n" ); document.write( "Equation for friend's house to Ahmad's house:
\n" ); document.write( "(2) $\"+d+=+50%2A%28+11+-+t+%29+\"$
\n" ); document.write( "-----------------------
\n" ); document.write( "By substitution:
\n" ); document.write( "(2) $\"+60t+=+50%2A%28+11+-+t+%29+\"$
\n" ); document.write( "(2) $\"+60t+=+550+-+50t+\"$
\n" ); document.write( "(2) $\"+110t+=+550+\"$
\n" ); document.write( "(2) $\"+t+=+5+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+d+=+60t+\"$
\n" ); document.write( "(1) $\"+d+=+60%2A5+\"$
\n" ); document.write( "(1) $\"+d+=+300+\"$
\n" ); document.write( "It is 300 miles to Ahmad's friend's house
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+d+=+50%2A%28+11+-+t+%29+\"$
\n" ); document.write( "(2) $\"+300+=+50%2A%28+11+-+5+%29+\"$
\n" ); document.write( "(2) $\"+300+=+50%2A6+\"$
\n" ); document.write( "(2) $\"+300+=+300+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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