document.write( "Question 935181: Sam is 9 years older than nick. 7 years ago he was 4 times as old as nick. how old is same now? \n" ); document.write( "
Algebra.Com's Answer #568324 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! x = Nick's age now \n" ); document.write( "x + 9 = Sam's age now {Sam is 9 years older than Nick}\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - 7 = Nick's age 7 years ago \n" ); document.write( "x + 2 = Sam's age 7 years ago {subtracted 7 from age now}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 2 = 4(x - 7) {seven years ago, Sam was four times Nick} \n" ); document.write( "x + 2 = 4x - 28 {used distributive property} \n" ); document.write( "3x = 30 {added 28 and subtracted x from each side} \n" ); document.write( "x = 10 {divided each side by 3} \n" ); document.write( "x + 9 = 19 {substituted 10, in for x, into x + 9}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sam is 19 \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |