document.write( "Question 935151: whats the magnitude and direction of a plane teaveling 120 killimeter per 1 hour for an hour and 30 min then turns and goes 45 degrees west and north at 150 kilomiters per hour for 3hours \n" ); document.write( "
Algebra.Com's Answer #568314 by stanbon(75887)\"\" \"About 
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whats the magnitude and direction of a plane traveling 120 killimeter per 1 hour for an hour and 30 min then turns and goes 45 degrees west and north at 150 kilomiters per hour for 3hours
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\n" ); document.write( "1st leg DATA:
\n" ); document.write( "x-coordinate:: time*rate*cos(bearing) = 1.5*120*cos(?)
\n" ); document.write( "y-coordinate:: tim*rate*sin(bearing) = 1.5*120*sin(?)
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\n" ); document.write( "Comment:: You did not post the bearing for the 1st leg,
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\n" ); document.write( "2nd leg DATA:
\n" ); document.write( "x-coordinate:: 3*150*cos(135) = -318.19
\n" ); document.write( "y-coordinate:: 3*150*sin(135) = 318.19
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\n" ); document.write( "Add the x-coordinates to get the coordinate of the finish point
\n" ); document.write( "Add the y-coordinates to get the coordinate of the finiah point.
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\n" ); document.write( "Assume those final coordinates are (a,b)
\n" ); document.write( "Then final bearing is tan^(-1)(b/a)
\n" ); document.write( "And final distance = sqrt[a^2+b^2]
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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