document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935156>Question 935156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mala diposited 25450 rps in a bank on 01/01/2006 . If the rate is 6% yearly then on 15/03/2007 how much rupees mala have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568313 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mala diposited 25450 rps in a bank on 01/01/2006 . If the rate is 6% yearly then on 15/03/2007 how much rupees mala have?<BR>\n" );
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document.write( "1 Jan 2006 to 15 March 2007 is 1 yr + 3.5 months = 1.2917 years<BR>\n" );
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document.write( "A(t) = P(1+(r/n))^(nt)<BR>\n" );
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document.write( "A(1.2917) = 25450(1 + (0.06/1))^(1*1.2917) = 25450*1.07817 = 27440 when<BR>\n" );
document.write( "rounded up.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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