document.write( "Question 935158: T is older than G, and the difference of their ages is 40. If forty years ago T was half as old as G will be in forty years, what is the sum of their ages? \n" ); document.write( "
Algebra.Com's Answer #568312 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! T is older than G, and the difference of their ages is 40. \n" ); document.write( "t = g + 40 \n" ); document.write( ": \n" ); document.write( "If forty years ago T was half as old as G will be in forty years, \n" ); document.write( "t - 40 = \n" ); document.write( "t - 40 = \n" ); document.write( "t = \n" ); document.write( "t = \n" ); document.write( "replace t with (g+40) \n" ); document.write( "g + 40 = \n" ); document.write( "g - \n" ); document.write( " \n" ); document.write( "multiply both sides by 2 \n" ); document.write( "g = 40 yrs \n" ); document.write( "therefore, obviously: \n" ); document.write( "t = 80 yrs \n" ); document.write( ": \n" ); document.write( " what is the sum of their ages? 120 yrs \n" ); document.write( " |