document.write( "Question 935158: T is older than G, and the difference of their ages is 40. If forty years ago T was half as old as G will be in forty years, what is the sum of their ages? \n" ); document.write( "
Algebra.Com's Answer #568312 by ankor@dixie-net.com(22740)\"\" \"About 
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T is older than G, and the difference of their ages is 40.
\n" ); document.write( "t = g + 40
\n" ); document.write( ":
\n" ); document.write( "If forty years ago T was half as old as G will be in forty years,
\n" ); document.write( "t - 40 = \"1%2F2\"(g+40)
\n" ); document.write( "t - 40 = \"1%2F2\"g + 20
\n" ); document.write( "t = \"1%2F2\"g + 20 + 40
\n" ); document.write( "t = \"1%2F2\"g + 60
\n" ); document.write( "replace t with (g+40)
\n" ); document.write( "g + 40 = \"1%2F2\"g + 60
\n" ); document.write( "g - \"1%2F2\"g + 60 - 40
\n" ); document.write( "\"1%2F2\"g = 20
\n" ); document.write( "multiply both sides by 2
\n" ); document.write( "g = 40 yrs
\n" ); document.write( "therefore, obviously:
\n" ); document.write( "t = 80 yrs
\n" ); document.write( ":
\n" ); document.write( " what is the sum of their ages? 120 yrs
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