document.write( "Question 935168: A ship leaves port at 12:00 pm (noon) and sails east at 10 miles per hour. Another leaves the same port at 1:00 pm and sails north at 20 miles per hour. At what time are the ships 50 miles apart? Show all your calculations. \n" ); document.write( "
Algebra.Com's Answer #568303 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A ship leaves port at 12:00 pm (noon) and sails east at 10 miles per hour. Another leaves the same port at 1:00 pm and sails north at 20 miles per hour. At what time are the ships 50 miles apart?
\n" ); document.write( "====================
\n" ); document.write( "t = 0 at 1 PM
\n" ); document.write( "Distance from port:
\n" ); document.write( "Eastbound = 10t + 10
\n" ); document.write( "Northbound = 20t
\n" ); document.write( "---
\n" ); document.write( "\"d%5E2+=+%2810t%2B10%29%5E2+%2B+%2820t%29%5E2\"
\n" ); document.write( "\"%2810t%2B10%29%5E2+%2B+%2820t%29%5E2+=+50%5E2+=+2500\"
\n" ); document.write( "\"100t%5E2+%2B+200t+%2B+100+%2B+400t%5E2+=+2500\"
\n" ); document.write( "\"500t%5E2+%2B+200t+%2B+100+=+2500\"
\n" ); document.write( "\"5t%5E2+%2B+2t+-+24+=+0\"
\n" ); document.write( "(5t + 12)*(t - 2) = 0
\n" ); document.write( "t = 2 hours (Ignore the negative solution)
\n" ); document.write( "--> 3 PM
\n" ); document.write( "
\n" );