document.write( "Question 935166: Mr Jagmohan calculated the average of 10 three digit numbers.But due to mistake he reversed the digits of a number and thus his average increased by 29.7.The difference between the ubits digit and hundreds digit of that no is:\r
\n" ); document.write( "\n" ); document.write( "a)4 b)3 c)2 d)cant be determined\r
\n" ); document.write( "\n" ); document.write( "What I have tried-------->
\n" ); document.write( "29.7 = 100a + 10b + c - 100c - 10b - a
\n" ); document.write( "29.7 = 99(a - c )
\n" ); document.write( "a - c = 0.3
\n" ); document.write( "But the answer is 3 ......how ?....why?..... Confused 😖 \r
\n" ); document.write( "\n" ); document.write( "Please help ...... \n" ); document.write( "

Algebra.Com's Answer #568301 by AnlytcPhil(1806) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "I think this is more complete, as it starts from scratch:\r\n" );
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document.write( "Let 100h+10t+u be the number that was reversed,\r\n" );
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document.write( "Let S = the sum of the 9 three-digit numbers that weren't reversed.\r\n" );
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document.write( "Then \r\n" );
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document.write( "average BEFORE reversing the number = \r\n" );
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document.write( "average AFTER reversing the number = \r\n" );
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document.write( "We are told that\r\n" );
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document.write( "Multiply through by 10\r\n" );
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document.write( "That simplifies to\r\n" );
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document.write( "Divide through by 99\r\n" );
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document.write( "They differ by 3.\r\n" );
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document.write( "Edwin

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