document.write( "Question 935166: Mr Jagmohan calculated the average of 10 three digit numbers.But due to mistake he reversed the digits of a number and thus his average increased by 29.7.The difference between the ubits digit and hundreds digit of that no is:\r
\n" ); document.write( "\n" ); document.write( "a)4 b)3 c)2 d)cant be determined\r
\n" ); document.write( "\n" ); document.write( "What I have tried-------->
\n" ); document.write( "29.7 = 100a + 10b + c - 100c - 10b - a
\n" ); document.write( "29.7 = 99(a - c )
\n" ); document.write( "a - c = 0.3
\n" ); document.write( "But the answer is 3 ......how ?....why?..... Confused 😖 \r
\n" ); document.write( "\n" ); document.write( "Please help ......
\n" ); document.write( "

Algebra.Com's Answer #568298 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Since the average increased by \"29.7\" and there were a total of \"10\" numbers, it means the incorrect number was \"29.7%2A10=297\" greater than the correct number.\r
\n" ); document.write( "\n" ); document.write( "Say, the correct number was \"abc\" (where \"a\", \"b\" and \"c\" are the digits of the \"3\" digit number)
\n" ); document.write( "Then the incorrect number was \"cba\".\r
\n" ); document.write( "\n" ); document.write( "\"100c+%2B+10b+%2B+a-%28100a+%2B+10b+%2B+c%29+=+297\"
\n" ); document.write( "\"99c-99a+=+297\"
\n" ); document.write( " \"99%28c-a%29=+297\"
\n" ); document.write( "\"%28c-a%29=+297%2F99\"
\n" ); document.write( "So \"c-a+=+3\"
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