document.write( "Question 935153: One year ago, sheela was four times as old as her daughter sakshi. Six years hence, sheela's age will exceed her daughter's age by 9 years. The ratio of the present ages of sheela and her daughter is
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Algebra.Com's Answer #568286 by vicgonzerx(31)\"\" \"About 
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let x=sheela (m0ther)----present age
\n" ); document.write( "y=daughter preent age
\n" ); document.write( "(x-1)=4(y-1)--------a year ago---eq 1
\n" ); document.write( "(x+6)=(y+6)+9-------6years hennce ----eq 2
\n" ); document.write( "x/y= required --------------?present \r
\n" ); document.write( "\n" ); document.write( "@ equation 1 \r
\n" ); document.write( "\n" ); document.write( "x-1=4y-4
\n" ); document.write( "x=4y-3-----then substitute to eq 2
\n" ); document.write( "x+6=y+15
\n" ); document.write( "4y-3+6=y+15
\n" ); document.write( "3y=15-6+3
\n" ); document.write( "y=4-----------------daughter age \r
\n" ); document.write( "\n" ); document.write( "then solve sheelas age \r
\n" ); document.write( "\n" ); document.write( "x-1=4(4-1)
\n" ); document.write( "x=13\r
\n" ); document.write( "\n" ); document.write( "then...the ratio is x/y=13/4--------------------\r
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