document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79166>Question 79166</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat moves 9 kilometers upstream in the same amount of time it moves 16 kilometers downstream. If the rate of the current is 6 kilometers per hour, find the rate of the boat still in the water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56828 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance=rate*time.<BR>\n" );
document.write( "9=(r-6)t upstream<BR>\n" );
document.write( "16=(r+6)t downstream.<BR>\n" );
document.write( "seeing as the times are equal we have:<BR>\n" );
document.write( "9/(r-6)=16/(r+6)<BR>\n" );
document.write( "16r-96=9r+54<BR>\n" );
document.write( "16r-9r=54+96<BR>\n" );
document.write( "7r=150<BR>\n" );
document.write( "r=21.43 kl/h speed of the boat in still water. <BR>\n" );
document.write( "proof<BR>\n" );
document.write( "9/(21.43-6)=16/(21.43+6)<BR>\n" );
document.write( "9/15.43=16/27.43<BR>\n" );
document.write( ".5833=.5833  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );