document.write( "Question 935139: Dear sir/madam,\r
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document.write( "Thank you or taking the time to help me solve my problem. Here it is:\r
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document.write( "Problem:\r
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document.write( "If the complement of an angle is 5° less than one-sixth of its supplement, find the measure of the angle.\r
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document.write( "My attempt: (I'm having trouble writing the equation!!!)\r
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document.write( "Complimentary angles = 90 degrees, therefore:\r
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document.write( "90 - a\r
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document.write( "Supplementary angles = 180 degrees therefore:\r
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document.write( "180 - 1/6a - 5\r
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document.write( "Therefore:\r
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document.write( "90 -a = 180 -1/6a - 5\r
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document.write( "6(90) - 6(a) = 6(180) - 6(1/6)a - 6(5)\r
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document.write( "540 - 6a = 1080 - a - 30\r
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document.write( "540 - 6a = 1050 - a\r
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document.write( "540 - 540 - 6a = 1050 - 540 - a\r
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document.write( "- 6a = 510 - a
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document.write( "- 6a + a = 510\r
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document.write( "- 5a = 510\r
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document.write( "- 5a/5 = 510/5\r
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document.write( "-a = 102\r
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document.write( "a = - 102\r
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document.write( "Obviously an angle can't be negative so I must have written the wrong equation.\r
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document.write( "Any help you could provide would be most appreciated.\r
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document.write( "Kindest regards,\r
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document.write( "Mark Beaton \n" );
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Algebra.Com's Answer #568268 by mananth(16946)![]() ![]() You can put this solution on YOUR website! If the complement of an angle is 5° less than one-sixth of its supplement, find the measure of the angle.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ";et angle be x \n" ); document.write( "complimentary angle = (90-x)\r \n" ); document.write( "\n" ); document.write( "supplementary angle = (180-x) \n" ); document.write( "0n-sixth = (180-x)/6 \n" ); document.write( "5 less than = (180-x)/6 - 5\r \n" ); document.write( "\n" ); document.write( "(90-x) =((180-x)/6) -5\r \n" ); document.write( "\n" ); document.write( "90+5 = (180-x)/6 +x\r \n" ); document.write( "\n" ); document.write( "95 = (180-x+6x)/6 \n" ); document.write( "570 = 180+5x \n" ); document.write( "390 = 5x\r \n" ); document.write( "\n" ); document.write( "x= 78 deg\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |