document.write( "Question 79171: The units digit of a two digit number is 1 less than 3 times the tens digit. If the digits are reversed, the new number is 45 more than the original number. Find the number. \n" ); document.write( "
Algebra.Com's Answer #56825 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! let 10x+y be the 2 digit number. then: y=(3x-1) \n" ); document.write( "10y+x=(10x+y)+45 \n" ); document.write( "now substituting (3x-1) for y in this equation we get \n" ); document.write( "10(3x-1)+x=10x+(3x-1)+45 \n" ); document.write( "30x-10+x=10x+3x-1+45 \n" ); document.write( "30x+x-10x-3x=-1+45+10 \n" ); document.write( "18x=54 \n" ); document.write( "x=54/18 \n" ); document.write( "x=3 answer \n" ); document.write( "y=3*3-1 \n" ); document.write( "y=9-1 \n" ); document.write( "y=8 answer. therefore the two numbers are: \n" ); document.write( "38 & 83 \n" ); document.write( "the difference is \n" ); document.write( "83-38=45 \n" ); document.write( "45=45 \n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |