document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935116>Question 935116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If (x + 2) is a factor of x^3 &#8722; 6x^2 + kx + 10, k = </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568233 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If (x + 2) is a factor of x^3 &#8722; 6x^2 + kx + 10, k =<BR>\n" );
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document.write( "If (x+2) is a factor, x = -2 is a zero or root.<BR>\n" );
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document.write( "Using synthetic division::<BR>\n" );
document.write( "-2)....1....-6....k....10<BR>\n" );
document.write( ".......1....-4....k-8..|..-2(k-8)+10<BR>\n" );
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document.write( "Solve::<BR>\n" );
document.write( "-2(k-8)+10 = 0<BR>\n" );
document.write( "-2k + 16 + 10 = 0<BR>\n" );
document.write( "-2k = 26 = 0<BR>\n" );
document.write( "k = 13<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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