document.write( "Question 935077: Find the value of p and q if:\r
\n" ); document.write( "\n" ); document.write( "(x-3) and (x+1) are factors of x^3+px+q\r
\n" ); document.write( "\n" ); document.write( "Where (x-3) I identified the answer as 3p+27+q (Equation 1)\r
\n" ); document.write( "\n" ); document.write( "Where (x+1) I identified the answer as -p-1+q (Equation 2)\r
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\n" ); document.write( "\n" ); document.write( "I thought that I would need to use synthetic division for both factors; then when I had the answer from each I'd use simultaneous equation to solve for one term, substitute it into the equation, then simplify for the second term.\r
\n" ); document.write( "\n" ); document.write( "So for p; I thought 4p=28; p=6\r
\n" ); document.write( "\n" ); document.write( "and for q; I got utterly lost tbh.\r
\n" ); document.write( "\n" ); document.write( "If I substitute the value for p where p=6 into Equation 1; I got q=45\r
\n" ); document.write( "\n" ); document.write( "But if I substitute the value for p where p=6 into Equation 2; I got -7.\r
\n" ); document.write( "\n" ); document.write( "The book says p=-6 and q=-7\r
\n" ); document.write( "\n" ); document.write( "So now I am bewildered where Ive gone wrong\r
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Algebra.Com's Answer #568201 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "you did this:
\n" ); document.write( "\"%28x-3%29\" identified the answer as \"3p%2B27%2Bq\".... (Equation 1)
\n" ); document.write( " \"%28x%2B1%29\" identified the answer as \"-p-1%2Bq\" .....(Equation 2) \r
\n" ); document.write( "\n" ); document.write( "just solve this system\r
\n" ); document.write( "\n" ); document.write( "\"3p%2B27%2Bq\".... (Equation 1)
\n" ); document.write( "\"-p-1%2Bq\" .....(Equation 2)
\n" ); document.write( "__________________________subtract eq.2 from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"3p%2B27%2Bq+-%28-p-1%2Bq+%29=0+\" \r
\n" ); document.write( "\n" ); document.write( "\"3p%2B27%2Bcross%28q%29+%2Bp%2B1-cross%28q%29+=0\" \r
\n" ); document.write( "\n" ); document.write( "\"3p%2B27+%2Bp%2B1+=0\"
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\n" ); document.write( "\"4p%2B28+=0+\" \r
\n" ); document.write( "\n" ); document.write( "\"4p+=-28\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28p+=-7%29\"\r
\n" ); document.write( "\n" ); document.write( "go to eq.2 plug in value for \"p\"\r
\n" ); document.write( "\n" ); document.write( "\"-p-1%2Bq\" .....(Equation 2)\r
\n" ); document.write( "\n" ); document.write( "\"-%28-7%29-1%2Bq+=0+\" \r
\n" ); document.write( "\n" ); document.write( "\"7-1%2Bq+=0+\"
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\n" ); document.write( "\"6%2Bq+=0++\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28q=-6%29\"\r
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