document.write( "Question 935077: Find the value of p and q if:\r
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document.write( "(x-3) and (x+1) are factors of x^3+px+q\r
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document.write( "Where (x-3) I identified the answer as 3p+27+q (Equation 1)\r
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document.write( "Where (x+1) I identified the answer as -p-1+q (Equation 2)\r
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document.write( "I thought that I would need to use synthetic division for both factors; then when I had the answer from each I'd use simultaneous equation to solve for one term, substitute it into the equation, then simplify for the second term.\r
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document.write( "So for p; I thought 4p=28; p=6\r
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document.write( "and for q; I got utterly lost tbh.\r
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document.write( "If I substitute the value for p where p=6 into Equation 1; I got q=45\r
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document.write( "But if I substitute the value for p where p=6 into Equation 2; I got -7.\r
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document.write( "The book says p=-6 and q=-7\r
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document.write( "So now I am bewildered where Ive gone wrong\r
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Algebra.Com's Answer #568201 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "you did this: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "just solve this system\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "__________________________subtract eq.2 from eq.1\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "go to eq.2 plug in value for \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |