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Algebra.Com's Answer #568198 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "angle CDE = Angle CED ( Given)\r
\n" ); document.write( "\n" ); document.write( "Therefore CD congruent - CE ( converse of Isosceles angle theorem)\r
\n" ); document.write( "\n" ); document.write( "But CD = BE given\r
\n" ); document.write( "\n" ); document.write( "Therefore CE = BE\r
\n" ); document.write( "\n" ); document.write( "Therefore angle ECB = angle EBC ( isosceles angle theorem)........(1)\r
\n" ); document.write( "\n" ); document.write( "In triangle CED angle CEB = angle ECD + angle EBC ( exterior angle theorem)\r
\n" ); document.write( "\n" ); document.write( "Therefore angle CEB = 2 angle EBC ( angle ECB = angle EBC ) from (1)\r
\n" ); document.write( "\n" ); document.write( "angle DCA + angle DAC = angle CDE ( exterior angle theorem)\r
\n" ); document.write( "\n" ); document.write( "But angle CDE =angle CED ( Isosceles Triangle)\r
\n" ); document.write( "\n" ); document.write( "angle DCA + angle DAC=angle ECD + angle EBC = 2angle B\r
\n" ); document.write( "\n" ); document.write( "Therefore angle CED = angle DCA + angle DAC =2 angle B\r
\n" ); document.write( "\n" ); document.write( "Therefore angle A = angle B\r
\n" ); document.write( "\n" ); document.write( "Therefore AC = BC ( converse of isosceles angle theorem\r
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